Tuesday, January 24, 2012
Monday, January 23, 2012
The nature of democracy
From Znet
The media therefore presents gossip not in spite of American democracy, but to enhance and preserve a certain conception of it: one that involves spectators, not participants; public ratification, not public decision making. It is antithetical to a participatory economy and the idea of self-governance, and displays a striking commitment to reactionary ideology, despite illusions of an independent press. The issue at hand is and will always be whether or not the media is free, but will remain unresolved as long as the media is responsible for the gossip that debases public life.
William E. Shaub is a violin performance major at the Juilliard School of Music in Manhattan and the editor of TheFBM.com.
How true. Yukie says that in Japan scandals are more about connections to unpopular groups or money scandals. At least that appears to have some political relevance...though it rarely does...
Sunday, January 22, 2012
http://www.nytimes.com/2012/01/22/sunday-review/hard-truths-about-disclosure.html?hp
To illustrate how few people actually read its terms and conditions disclosure, the online retailer Gamestation, on April Fools’ Day 2010, replaced the usual text with what it called an “immortal soul clause,” which read: “By placing an order via this Web site on the first day of the fourth month of the year 2010 anno Domini, you agree to grant us a non-transferable option to claim, for now and forever more, your immortal soul.” Eager to get on with their online purchase, 88 percent of customers clicked the box to sell their souls. (The 12 percent who opted out were rewarded with a cash credit for their diligence.)
Monday, January 09, 2012
factorial functionSSSSS
Abstract. The Gamma function of Euler often is thought as the only function which interpolates the factorial numbers n! = 1,2,6,24,.... This is far from being true. We will discuss four factorial functions
the Euler factorial function n!,
the Hadamard Gamma function H(n),
the logarithmic single inflected factorial function L(n),
the logarithmic single inflected hyper-factorial function L*(n).
We will show that these alternative factorial functions posses qualities which are missing from the the conventional factorial function but might be desirable in some context.
Thursday, January 05, 2012
how big of a mammal are we operating at?
rest state 100 watts
as a social animal...15,000
more than biggest mammal blue whale
Wednesday, January 04, 2012
A castle without a dragon is worse than no castle at all.
The idea of creative play as conducive to learning, or even formal education, is an article of faith at Lego that goes back to its founder, who defended his decision to become a toymaker during the Great Depression by pointing out that all animals use play to develop their brains. In Japan, however, Lego found that study and play were more clearly delineated. Few Japanese parents bought Lego, as they do in Germany or the U.S., because they were “toys with vitamins in them,” as Lego senior director Søren Holm only half-jokingly puts it.
American boys, meanwhile, turned out to be the least free of any group Lego tracked. British and German boys are far more likely to play unsupervised in yards and wooded areas and even have greater latitude in decorating their bedroom walls. Among slightly older American boys, 9 to 12, building with Lego represented a rare chance to be left alone. (On one subject, boys of all ages and nationalities agreed: A castle without a dragon is worse than no castle at all.)
Tuesday, January 03, 2012
- Method 1. Given any homogeneous polynomial
f of degreen inm indeterminates over a commutative scalar ringR (scalar simply means that the elements ofR commute with the indeterminates).
- Step 1
- If all indeterminates are linear in
f , then we are done. - Step 2
- Otherwise, pick an indeterminate
x such thatx is not linear inf . Without loss of generality, writef=f(x , whereX)
X is the set of indeterminates inf excludingx . Defineg(x1 . Thenx2
X):=f(x1+x2
X)−f(x1
X)−f(x2
X)
g is a homogeneous polynomial of degreen inm+1 indeterminates. However, the highest degree ofx1 isx2
n−1 , one less that ofx . - Step 3
- Repeat the process, starting with Step 1, for the homogeneous polynomial
g . Continue until the setX of indeterminates is enlarged to oneX such that eachx is linear.X
- Method 2. This method applies only to homogeneous polynomials that are also homogeneous in each indeterminate, when the other indeterminates are held constant, i.e.,
f(tx for someX)=tnf(x
X)
n and anyt . Note that if all of the indeterminates inR
f commute with each other, thenf is essentially amonomial. So this method is particularly useful when indeterminates are non-commuting. If this is the case, then we use the following algorithm:
- Step 1
- If
x is not linear inf and thatf(tx , replaceX)=tnf(x
X)
x with a formal linear combination ofn indeterminates overR :r1x1+ +rnxn, where ri
R
- Step 2
- Define a polynomial
g , the non-commuting free algebra overR
x1
xn
R (generated by the non-commuting indeterminatesxi ) by:g(x1 xn):=f(r1x1+
+rnxn)
- Step 3
- Expand
g and take the sum of the monomials ing whose coefficent isr1 . The result is a linearization ofrn
f for the indeterminatex . - Step 4
- Take the next non-linear indeterminate and start over (with Step 1). Repeat the process until
f is completely linearized.
- The method of linearization is used often in the studies of Lie algebras, Jordan algebras, PI-algebras and quadratic forms.
- If the characteristic of scalar ring
R is 0 andf is a monomial in one indeterminate, we can recoverf back from its linearization by setting all of its indeterminates to a single indeterminatex and dividing the resulting polynomial byn! :Please see the first example below.f(x)=1n!linearization(f)(x x)
- If
f is a homogeneous polynomial of degreen , then the linearizedf is a multilinear map inn indeterminates.
f(x)=x2 . Thenf(x1+x2)−f(x1)−f(x2)=x1x2+x2x1 is a linearization ofx2 . In general, iff(x)=xn , then the linearization off iswhereSnx
(1)
x
(n)=
Sn
ni=1x
(i)
Sn is the symmetric group on . If in addition all the indeterminates commute with each other and1
n
n! in the ground ring, then the linearization becomes=0
n!x1 xn=
ni=1ixi